关于arx中的尺寸
亲爱的成员们，任何人都知道如何在arx中创建维度
在autolisp中，我将使用_。dimaligned
(setqpt1 (list 5 5))
(setqpt2 (list 10 10))
(command "line" pt1 pt2 "")
(command "_.dimaligned" pt1 pt2 (polar pt2 01))
带有代码的简单示例会很好workingDatabase();
AcDbBlockTableRecordPointer pBlockTableRecord(pDatabase->currentSpaceId(),AcDb::kForWrite);
AcDbAlignedDimension *dim = new AcDbAlignedDimension (pr1.Point,pr2.Point,pr3.Point);
dim->setDatabaseDefaults(pDatabase);
pBlockTableRecord->appendAcDbEntity(dim);
dim->close();
}
你好Daniel，
我使用了你之前的代码，只是修改了一些以使用我的数据库。
以下代码在autocad中抛出错误对话框。
是否有我丢失的东西？如果我使用workingDatabase，它不会报告此错误。
关于，
Pawan
int test_save()
{
AcDbDatabase *pDb = new AcDbDatabase();
AcDbBlockTable *pBtbl;
pDb->getSymbolTable(pBtbl, AcDb::kForRead);
AcDbBlockTableRecord *pBtblRcd;
pBtbl->getAt(ACDB_MODEL_SPACE, pBtblRcd, AcDb::kForWrite);
pBtbl->close();
////////////////dim starts
ads_point pt1 = {5,10};
ads_point pt2 = {15,10};
ads_point pt3 = {10,10};
ads_point temp = {10,10};
ads_real tAngle = 0;
AcGePoint3d stpt(asPnt3d(pt1)); //3d starting point
AcGePoint3d endpt(asPnt3d(pt2));; //3d ending point
acutPolar(pt3, tAngle, 0, temp);
AcGePoint3d dimPoint(asPnt3d(temp)); //3d dim point
// if i use working database, this doesn't give error
// AcDbDatabase *pDb= acdbHostApplicationServices()->workingDatabase();
// AcDbBlockTableRecordPointer pBtblRcd(pDb->currentSpaceId(),AcDb::kForWrite);
AcDbAlignedDimension *dim = new AcDbAlignedDimension (stpt,endpt,dimPoint);
dim->setDatabaseDefaults(pDb);
pBtblRcd->appendAcDbEntity(dim);
dim->close();
////////////////dim ends
//close the blocktable record
pBtblRcd->close();
//save the file
Acad::ErrorStatus es = pDb->saveAs(_T("c:\\temp\\test.dwg"));
//delete the database
delete pDb;
return 0;
}
永远不要假设返回Acad::ErrorStatus的函数将返回Acad::eOk，检查它们。很肯定你会发现你描述的问题。 我发现了问题。
AcDbAlignedDimension*dim=new AcDbAlignedDimension（stpt， endpt， dimPoint）；
与新数据库一起使用时，AcDbAlignedDimension（）需要dimstyle。
这就是它之前报告错误的原因。
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