创建等轴测坡度图案填充
大家好，我主要在管道行业工作，我们不使用Autocad 3D Plant，因为我们不在设计行业，而是在维护行业。也就是说，我们没有管道坡度图案填充功能。有关坡度图案填充示例，请参见照片。我们用这个表示45度，45度和90度的肘部。如果有人能插话分享一些对我们有帮助的东西，帮助我们快速自动创建这个舱口，我将不胜感激。
你试过用板条舱口的区域吗？ 我自己从未使用过iso，但我为我的同事编写了一个程序，RlxIso。如果我有空闲时间，我可以问他们这应该怎么做，也许可以更新我的程序（如果他们有兴趣的话）。在我看来，它就像一个等距三角形，用户图案填充为90度。现在，我正在工作的工厂正处于重大停工期间，所以不确定我是否很快有时间。
gr.Rlx 也许可以进一步解释一下基本bhatch函数无法提供的功能。无论iso是2d还是3d视图，bhatch都可以正常工作，所以我猜你想要更多？ 为了澄清，现在我的办公室必须手动绘制直角三角形（即使用简单的直线命令或偏移命令），然后根据角度是垂直角度还是水平角度应用阴影。
我的问题与lisp有关，lisp可以自动创建三角形和图案填充（我应该在标题中更具体一些，但AutoCAD Plant 3D就是这么称呼它的）。然而，由于这是基本的cad操作，我们可以整天手动绘制、修剪和填充这些图形，没有任何问题。失败之处在于，在整个管道回路中有几十个角度，每天都有几十个角度需要完成。
我需要有人来帮助与lisp例程自动化三角形和阴影在一个或两个点击。这是我的程序的屏幕截图来展示示例。第一幅图像取自AutoCAD Plant 3D，仅供参考。
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dymanics perhaps?
ISO hatch.dwg This looked like an interesting program to write - please try the following (adjust the settings at the top to suit):
;;----------------------=={ Isometric Triangle }==----------------------;;;; ;;;;Prompts the user to pick two points at a non-isometric angle and ;;;;proceeds to construct a hatched isometric right-angled triangle, ;;;;offset from the two given points by a distance specified in the ;;;;code. ;;;;----------------------------------------------------------------------;;;;Author:Lee Mac, Copyright © 2015-www.lee-mac.com ;;;;----------------------------------------------------------------------;;;;Version 1.0 - 2015-10-06 ;;;; ;;;;- First release. ;;;;----------------------------------------------------------------------;;;;Version 1.1 - 2015-10-10 ;;;; ;;;;- Removed restriction on non-isometric angles (e.g. 60 deg). ;;;;----------------------------------------------------------------------;;(defun c:isotri ( / an1 an2 div err hat hpa off pat pi6 ply pt1 pt2 scl spc vt1 vt2 vt3 ) (setq off 1.0 ;; Triangle offset pat "ANSI31" ;; Hatch pattern name hpa (/ pi 4.0) ;; Hatch angle scl 0.1 ;; Hatch scale ) (cond ( (not (and (setq pt1 (getpoint "\nPick 1st point: ")) (setq pt2 (getpoint "\nPick 2nd point: " pt1)) ) ) ) ( (progn (defun div ( x m / r ) (setq r (rem x m)) (or (equal 0.0 r 1e-6) (equal m r 1e-6)) ) (setq an1 (angle pt1 pt2) pi6 (/ pi 6.0) ) (and (div an1 pi6) (not (div an1 (+ pi6 pi6)))) ) (princ "\nCannot generate triangle for isometric angle.") ) ( (or ( Humm I tried your code lee. I am selecting both end points of the line Iwish to create the hatched triangle for but keep getting the message-"Cannot generate triangle for isometric angle."... In our industry wedraw strictly in isometric and these are indeed isometric angles.However, when I draw lines straight up and straight right(90 and 180degrees) then run the code and pick my two points, it pops in aisometric triangle like what is shown in the image that I will attach.https://www.cadtutor.net/forum/attachment.php?attachmentid=55717&cid=1&stc=1https://www.cadtutor.net/forum/attachment.php?attachmentid=55718&cid=1&stc=1
Now here is the depiction of what we would actually need.. Thanks againfor everything by the way this is extremely generous of you. Excellenthard work!https://www.cadtutor.net/forum/attachment.php?attachmentid=55724&cid=1&stc=1
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