路径阵列
大家好，我试图沿路径排列一个块，使块上的两个点与路径相交，并且这些点彼此重合。
与下图类似，如果线所在的地方有块。
我尝试了内置的路径数组以及测量和除法命令，但没有成功。
感谢您的帮助。
当做 这是一个vba程序，允许沿pline插入块。它基本上可以满足您的需要，但需要修改以满足您的块长度需要。我将代码作为源代码发布，它基本上需要2个点，并使用intersectwith来计算块角度。我们用它来检查车辆的车道。
Sub draw_vehicle()
Dim CAR As String
Dim arcobj As AcadArc
Dim oPoly As AcadEntity
Dim blkobj As AcadEntity
Dim retVal As Variant
Dim snapPt As Variant
Dim oCoords As Variant
Dim blpnt1() As Variant
ReDim blpnt1(100)
Dim blpnt2() As Variant
ReDim blpnt2(100)
Dim vertPt(0 To 2) As Double
Dim Pt1(0 To 2) As Double
Dim Pt2(0 To 2) As Double
Dim newPt(0 To 2) As Double
Dim iCnt, w, x, y, z As Integer
Dim cRad, interval, blkangle As Double
Dim circObj As AcadCircle
Dim lineObj As AcadLine
On Error GoTo Something_Wrong
If ThisDrawing.ActiveSpace = acModelSpace Then
Set Thisspace = ThisDrawing.ModelSpace
Else: Set Thisspace = ThisDrawing.PaperSpace
End If
For Each Item In ThisDrawing.Blocks
If Item.Name = "holden" Then GoTo continue_on
Next Item
' insert holden block
InsertBlock "p:\Autodesk\vba\holdencar.dwg", 0
continue_on:
w = 1
ThisDrawing.Utility.GetEntity oPoly, snapPt, vbCr & "Select polyline :"
If oPoly.ObjectName = "AcDbPolyline" Then
oCoords = oPoly.Coordinates
Else: MsgBox "This object is not a polyline! Please do again"
Exit Sub
End If
interval = CDbl(InputBox("Enter interval:", , 1#))
If interval < 1 Then
interval = 1
End If
For iCnt = 0 To UBound(oCoords) - 2 Step 2
Pt1(0) = oCoords(iCnt): Pt1(1) = oCoords(iCnt + 1): Pt1(2) = 0#
newPt(0) = Pt1(0)
newPt(1) = Pt1(1)
newPt(2) = 0#
iCnt = iCnt + 2
Pt2(0) = oCoords(iCnt): Pt2(1) = oCoords(iCnt + 1): Pt2(2) = 0#
x = (Pt1(0) - Pt2(0)) / interval
y = (Pt1(1) - Pt2(1)) / interval
'reset back 2 values
iCnt = iCnt - 2
cRad = 3.05
startang = 4.71239
endang = 1.570796
CAR = "HOLDEN"
For z = 1 To interval
vertPt(0) = newPt(0) - x
vertPt(1) = newPt(1) - y
vertPt(2) = 0#
'blpnt1(w) = vertPt
'Set arcobj = ThisDrawing.ModelSpace.AddArc(vertPt, cRad, endang, startang)
Set arcobj = Thisspace.AddArc(vertPt, cRad, endang, startang)
retval2 = arcobj.IntersectWith(oPoly, acExtendOtherEntity)
arcobj.Delete
Set arcobj = Nothing
blkangle = ThisDrawing.Utility.AngleFromXAxis(retval2, vertPt)
'Set blkobj = ThisDrawing.ModelSpace.InsertBlock(vertPt, CAR, 1#, 1#, 1#, blkangle)
Set blkobj = Thisspace.InsertBlock(vertPt, CAR, 1#, 1#, 1#, blkangle)
Set blkobj = Nothing
w = w + 1
newPt(0) = newPt(0) - x
newPt(1) = newPt(1) - y
Next z
Next iCnt
GoTo Exit_out
Something_Wrong:
MsgBox Err.Description
Exit_out:
End Sub
Function InsertBlock(ByVal blockpath As String, ByVal rotation As Double)
Dim blockobj As AcadBlockReference
Dim insertionPnt As Variant
Dim prompt1 As String
'set rotation Angle
rotateAngle = rotation
'rotateAngle = rotation * 3.141592 / 180#
'Prompt is used to show instructions in the command bar
prompt1 = vbCrLf & "Enter block insert point: "
'ThisDrawing.ActiveSpace = acModelSpace
insertionPnt = ThisDrawing.Utility.GetPoint(, prompt1)
Set blockRefObj = ThisDrawing.ModelSpace.InsertBlock(insertionPnt, blockpath, 1#, 1#, 1#, rotateAngle)
'Change Modelspace into Paperspace to insert the block into Paperspace
End Function
谢谢比格尔，这是一个很好的开始。我可以看到明显的变化，如路径和块名称等，但我想我会坚持修改，以适应我的块相交点是11590mm的距离。 只需更改Crad 3.05是车轮之间的距离，为了更准确，请使用PI的真实值作为VBA变量。Startang Endang，创建一个11590mm的块水平线给它你的名字，而不是霍尔顿应该工作的话。 好的，我设法让VBA运行，改变了一些事情，但没有任何运气得到它太阵列。该程序似乎不允许我在块上选择2个点，这将是路径上的交点，对吗？
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