arden 发表于 2005-12-7 17:36:00

[VBA]关于选择集

我想用一闭合多段线为边界选择其内部的图形,采用selectbypolygen方法,但发现与边界相连的多边形或线段都选不上,如下图,有其它方法吗?
d:\未命名.bmp

莫名 发表于 2005-12-7 22:27:00

object.SelectByPolygon Mode, PointsList, FilterType, FilterData
Mode用acSelectionSetCrossingPolygon

arden 发表于 2005-12-8 14:48:00

莫名你好,如果Mode采用acSelectionSetCrossingPolygon 的话与边界相连的外面的多边形也会被选中。我主要是用来计算图斑面积时扣除内部图斑的面积,不知有没有好一点的办法。
d:\未命名.bmp

arden 发表于 2005-12-22 13:37:00

沉到底了,自己顶一下,大家给个答案啊

arden 发表于 2006-1-4 14:41:00

自己顶

arden 发表于 2006-1-5 14:57:00



程序如下:
Sub selectPl()
    Dim ent As AcadEntity
    Dim SelObj As AcadEntity
    Dim NumSel As Integer
    Dim Coord As Variant
    Dim CoordCount As Integer
    Dim NewCoord() As Double
    Dim i As Integer
   
    Dim ssetObj As AcadSelectionSet
    On Error GoTo Err1:
    Set ssetObj = ThisDrawing.SelectionSets.Add("TEST_SSET2")
   
    On Error Resume Next
    Do
      ThisDrawing.Utility.GetEntity ent, pnt, "选择多段线:"
      If Err Then Exit Sub
      If TypeName(ent) Like "IAcad*Polyline" Then Exit Do
    Loop
   
If TypeName(ent) = "IAcadLWPolyline" Then
      Coord = ent.Coordinates
      CoordCount = (UBound(Coord) + 1) / 2 '顶点数
      '定义新的顶点坐标数组
      ReDim NewCoord(0 To (3 * CoordCount - 1)) As Double
      For i = 0 To UBound(Coord) - 1 Step 2
            NewCoord((3 * i) / 2) = Coord(i)
            NewCoord((3 * i) / 2 + 1) = Coord(i + 1)
            NewCoord((3 * i) / 2 + 2) = 0
      Next i
ElseIf TypeName(ent) = "IAcadPolyline" Then
      Coord = ent.Coordinates
      CoordCount = (UBound(Coord) + 1) / 3
      ReDim NewCoord(0 To UBound(Coord)) As Double
      For i = 0 To UBound(Coord) - 1
            NewCoord(i) = Coord(i)
            NewCoord(i) = Coord(i)
            NewCoord(i) = Coord(i)
      Next
End If
ssetObj.SelectByPolygon acSelectionSetWindowPolygon, NewCoord
ssetObj.Highlight True
ssetObj.Update
NumSel = ssetObj.Count
Exit Sub
Err1:
    ThisDrawing.SelectionSets.Item("TEST_SSET2").Delete
    Resume
End Sub

arden 发表于 2006-1-10 20:00:00

还是自己顶,有人回答一下是如果根本没办法解决有话就不顶了
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