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发表于 2004-11-5 09:31:00
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比如说这一段程序,在模式对话框中就可以画图
AcGePoint3d startPt(4.0, 2.0, 0.0);
AcGePoint3d endPt(10.0, 7.0, 0.0);
AcDbLine *pLine = new AcDbLine(startPt, endPt);
AcDbBlockTable *pBlockTable;
acdbHostApplicationServices()->workingDatabase()
->getSymbolTable(pBlockTable, AcDb::kForRead);
AcDbBlockTableRecord *pBlockTableRecord;
pBlockTable->getAt(ACDB_MODEL_SPACE, pBlockTableRecord,
AcDb::kForWrite);
pBlockTable->close();
AcDbObjectId lineId;
pBlockTableRecord->appendAcDbEntity(lineId, pLine);
pBlockTableRecord->close();
pLine->close();
但是在非模式对话框中就画不了, 我调试了一下,pBlockTableRecord不能得到值
我查了一下资料,资料上说:AutoCAD 2000及以后版本,都是多文档环境,当用户的菜单项和对话框发布绘图命令时,应指定接受命令的文档,否则CAD将不予执行
但是我还是不知道怎么办? |
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