[求助]大侠:请教VB调用自定义函数的值传递问题

dance · 发表于 2006-5-14 22:35:00

我在编一个求点集凸包的程序
采点集的程序部分已经搞定
想把点集中y最近小且距x最远的点找到，就用二分法排了序，但数组p（）的值纵传不到数组pl()上。请在帮忙看下：
Option Explicit
Private Type pointinfo
x As Single                   '点的x 坐标值
y As Single                   '点的y 坐标值
q As Single                   '与水平线的夹角
End Type
Dim p0 As pointinfo
Dim p(0 To 200) As pointinfo '点集
Dim pl(0 To 200) As pointinfo '求出起始点
Dim ps(0 To 200) As pointinfo '排序后的点集
Dim pi(0 To 200) As pointinfo '极点
Dim n, m, d As Integer
Dim x0, y0 As Single
Dim l, e As Integer
Private Sub Form_MouseDown(Button As Integer, Shift As Integer, x As Single, y As Single)
DrawWidth = 4
If n = 0 Then
p(0).x = x
p(0).y = y
Circle (x, y), 100, RGB(255, 0, 255)
Else '输入点集
p(n).x = x
p(n).y = y
Circle (x, y), 10, RGB(255, 255, 0)
End If
n = n + 1
x0 = x
y0 = y

End Sub
Private Sub Command2_Click()
Dim i As Integer
Dim q As Single
p(n).x = x0
p(n).y = y0
Const pi = 3.14
Dim u, j As Integer
Dim k, r, f As Integer
Dim term As pointinfo
For u = 0 To n
  term = p(l)
  k = 0
  r = u - 0
  Do While k  Abs(pl(f).x))) Then
         r = f - 1
      Else
         k = f + 1
      End If
  Loop
  For j = u - 1 To k Step -1
   pl(j + 1) = pl(j)
  Next j
  pl(k) = term
Next u
End Sub

xinghesnak · 发表于 2006-5-15 09:20:00

呵呵！昨天公司休息，没有电脑能上网啊。。。。
dance，不怕你见笑，二分法我不明白。。。。要是我做，如果只是简单得到Y最
小X最大的数组，在command2的点击事件中这么写：
Private Sub Command2_Click()
Dim i As Integer
Dim term As pointinfo
term.x = p(0).x: term.y = p(0).y
For i = 1 To n - 1
If p(i).y term.x) Then
term.x = p(i).x: term.y = p(i).y
end if
Next
End Sub

xinghesnak · 发表于 2006-5-15 09:43:00

如果是排序，我这样写的：
Private Sub Command2_Click()
Dim i As Integer, j As Integer
Dim term As pointinfo
For i = 1 To n - 1
For j = 1 To n - i
      If p(j).y  p(j - 1).x) Then
         term.x = p(j - 1).x: term.y = p(j - 1).y
         p(j - 1).x = p(j).x: p(j - 1).y = p(j).y
         p(j).x = term.x: p(j).y = term.y
      End If
Next
Next
End Sub

dance · 发表于 2006-5-15 22:17:00

呵呵,这个方法很奏效.谢谢.
为了从p(0)开始计点，我把form-click()部分给改写了下。
但是我在往下编写求其他各点与排序后的极植点p(0)所在水平线的角度p(i).q时，又出现了值传递问题。p(i).q的值总是0，而不是程序的计算值。下面是我的程序：
Option Explicit
Private Type pointinfo
x As Single                   '点的x 坐标值
y As Single                   '点的y 坐标值
q As Single                   '与水平线的夹角
End Type
Dim p0 As pointinfo
Dim p(0 To 200) As pointinfo '点集
Dim pl(0 To 200) As pointinfo '求出起始点
Dim ps(0 To 200) As pointinfo '排序后的点集
Dim pi(0 To 200) As pointinfo '极点
Dim n, m, d As Integer
Dim x0, y0 As Single
Dim l, e As Integer
Private Sub Form_MouseDown(Button As Integer, Shift As Integer, x As Single, y As Single)
DrawWidth = 4
If n = 0 Then
p(0).x = x
p(0).y = y
Circle (x, y), 100, RGB(255, 0, 255)
Else '输入点集
p(n).x = x
p(n).y = y
Circle (x, y), 10, RGB(255, 255, 0)
End If
n = n + 1    '我后改写的部分
End Sub

Private Sub Command2_Click()
Dim i As Integer
Dim q As Single
Const pi = 3.14
Dim u As Integer, j As Integer                         '将p()排序y有小至大。
Dim term As pointinfo
For u = 1 To n - 1
For j = 1 To n - u
      If p(j).y
For i = 1 To n - 1                                        '我计算角度的程序
If p(i).y - p(0).y = 0 Then
      If p(i).x - p(0).x = 0 Then
         p(i).q = 90
      ElseIf p(i).x - p(0).x > 0 Then
      p(i).q = 180 / pi * Atn((p(i).y - p(0).y) / (p(i).x - p(0).x))
      Else
         p(i).q = 180 / pi * Atn((p(i).y - p(0).y) / (p(i).x - p(0).x)) + 180
      End If
ElseIf p(i).y - p(0).y  0 Then
      p(i).q = 360 + 180 / pi * Atn((p(i).y - p(0).y) / (p(i).x - p(0).x))
      Else
      p(i).q = 180 + 180 / pi * Atn((p(i).y - p(0).y) / (p(i).x - p(0).x))
      End If
End If

Next i
End Sub

xinghesnak · 发表于 2006-5-16 09:19:00

楼上的，你的程序可。。。。。。
If p(i).y - p(0).y = 0 Then 这句话是不是你的笔误啊，应该写成
If p(i).y - p(0).y> =0 Then ??

dance · 发表于 2006-5-17 15:38:00

呵呵，你是不是觉得俺的程序有点啰嗦
不好意思，总是边着编着出纰漏。

dance · 发表于 2006-5-17 15:43:00

我现在请问下，怎么清除一个自定义数组的一个值？
下面是后续程序
Private Sub Command3_Click()
Dim u As Integer, j As Integer                         '将p()排序q有小至大逆时针排序。
Dim term As pointinfo
For u = 1 To n - 1
For j = 1 To n - u
      If p(j).q
End Sub
Private Sub Command4_Click()
'找极点
Dim i, j As Integer
Dim s As Single
Dim inpv As Integer
pi(0) = p(0)
pi(1) = p(1)
m = 1
For d = 2 To n - 1
s = sarea(pi(m - 1), pi(m), p(d))
If s > 0 Then                '点在pv 数组尾的左侧
pi(m + 1) = p(d)
m = m + 1
Else:
pi(m) = p(d)             '点在pv 数组尾的右边侧
m = m - 1
End If
   m = m + 1

Next d
If s = sarea(pi(m - 1), pi(m), p(0))
For j = 0 To n - 1       '输出极边
Line (pi(j).x, pi(j).y)-(pi(j + 1).x, pi(j + 1).y)
Next j
Line (pi(n).x, pi(n).y)-(pi(0).x, pi(0).y)
End Sub

dance · 发表于 2006-5-17 15:46:00

抱歉，刚刚忘打自定义函数了
Private Function sarea(x As pointinfo, y As pointinfo, z As pointinfo) As Single
sarea = (x.x * y.y - x.y * y.x) + (y.x * z.y - y.y * z.x) + (z.x * x.y - z.y * x.x)
End Function

xinghesnak · 发表于 2006-5-17 16:26:00

清楚P(m)是什么意思？除掉这个数还是清除里面的数据？

dance · 发表于 2006-5-17 20:34:00

Private Type pointinfo
x As Single                   '点的x 坐标值
y As Single                   '点的y 坐标值
q As Single                   '与水平线的夹角
End Type
Dim p(0 To 200) As pointinfo
p(m)为其中的一个值

[求助]大侠:请教VB调用自定义函数的值传递问题

发表回复

精选推荐