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大家好,我想用vba判断块的 Visibility的属性是“45度”还是“60度”,如何写代码?谢谢
有如下两种:
{ Block Name: "YTZK"
Anonymous Name: "*U192"
at point, X=3145.00000000 Y=3930.00000000 Z=0.00000000
X scale factor: 1.00000000
Y scale factor: 1.00000000
rotation angle: 49
Z scale factor: 1.00000000
Scale uniformly: No
Allow exploding: Yes
Visibility: 45度}
{Block Name: "YTZK" Anonymous Name: "*U200" at point, X=3145.00000000 Y=3930.00000000 Z=0.00000000 X scale factor: 1.00000000 Y scale factor: 1.00000000 rotation angle: 49 Z scale factor: 1.00000000 Scale uniformly: No Allow exploding: Yes Visibility: 60度} |
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