发表于 2009-10-3 12:03:00
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转过去的链接中大家讨论得已经比较详细了,我比较喜欢mccad大虾的思路,但是我觉得他所提供的函数中有一点点瑕疵,最起码我用
"\A1;\{{\H1.6x;A}\P{\LB}\P{\H1.6x;C;}\P\pi0.999306,l2.99792,t7;{\fCorbel|b0|i0|c0|p34;D}\P\pi0,l0,tz;{\C1;E}\PF?\PG\\\Ph{\H0.7x;\S1/2;}\PJ{\H0.7x;\S2^;}\PK{\H0.7x;\S^2;}|\PL"
这个字符串作核试验的时候就不完全正确,而且稍显繁复,所以我重新总结了一下,得出下面的两个函数,请众位同好不吝指正
第一个是用RegExp来替换的自定义函数
Public Function ReplaceByRegExp(ByVal Mystrig As String, ByVal TxtFind As String, ByVal TxtReplace As String)
Dim RE As Object
Set RE = ThisDrawing.Application.GetInterfaceObject("Vbscript.RegExp")
RE.IgnoreCase = False
RE.Global = True
RE.Pattern = TxtFind
ReplaceByRegExp = RE.Replace(Mystrig, TxtReplace)
Set RE = Nothing
End Function
第二个是用来清除多行字格式的函数
Public Function MtextStringClearFormat(ByVal MyString As String) As String
MyString = ReplaceByRegExp(MyString, "\\{", Chr(1))
MyString = ReplaceByRegExp(MyString, "\\}", Chr(2))
MyString = ReplaceByRegExp(MyString, "\\", Chr(3))
MyString = ReplaceByRegExp(MyString, "\\S([^;]*?)(\^|#)([^;]*?);", "$1$3")
MyString = ReplaceByRegExp(MyString, "\\S([^;]*?);", "$1")
MyString = ReplaceByRegExp(MyString, "(\\P|\\O|\\o|\\L|\\l|\{|\})", "")
MyString = ReplaceByRegExp(MyString, "\\[^;]*?;", "")
MyString = ReplaceByRegExp(MyString, "\x01", "{")
MyString = ReplaceByRegExp(MyString, "\x02", "}")
MyString = ReplaceByRegExp(MyString, "\x03", "")
MtextStringClearFormat = Trim(MyString)
End Function
最后写一个测试过程
Sub TEST()
Dim TxtOld As String
Dim TxtNew As String
TxtOld = "\A1;\{{\H1.6x;A}\P{\LB}\P{\H1.6x;C;}\P\pi0.999306,l2.99792,t7;{\fCorbel|b0|i0|c0|p34;D}\P\pi0,l0,tz;{\C1;E}\PF?\PG\\\Ph{\H0.7x;\S1/2;}\PJ{\H0.7x;\S2^;}\PK{\H0.7x;\S^2;}|\PL"
TxtNew = MtextStringClearFormat(TxtOld)
End Sub
大家再帮我用其它的字符串测试一下,看看是不是有所遗漏或是BUG,谢谢了