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按照14.2创建数据表的要求做了一个3DSolid,一个line
0gjt2tyzihf.jpg
碰到的问题是在 3Dsolid 在加入到VBASample.mdb数据库中,从debug.print 得到了3DSolid的ID号是2129993344,但ID号就是不能添加到数据库中.
第339页的程序摘录
For Each obj In ThisDrawing.ModelSpace
Debug.Print obj.ObjectName
Debug.Print obj.ObjectID
Select Case obj.ObjectName
Case "AcDbLine":
rst.Open "SELECT id FROM line", cn, adOpenForwardOnly, adLockReadOnly, adCmdText
pt1 = obj.StartPoint
pt2 = obj.EndPoint
If Not FindObj(rst, obj.ObjectID) Then ' 新建的直线的处理
cmd.CommandText = "INSERT INTO line(id,X1,Y1,X2,Y2) VALUES(" & _
"'" & obj.ObjectID & "'," & pt1(0) & "," & pt1(1) & "," & pt2(0) & "," & pt2(1) & ");"
Else ' 修改的直线的处理
cmd.CommandText = "UPDATE line SET X1=" & pt1(0) & ",Y1=" & pt1(1) & ",X2=" & _
pt2(0) & ",Y2=" & pt2(1) & " WHERE id='" & obj.ObjectID & "';"
End If
cmd.Execute
rst.Close
Case "AcDbCircle":
rst.Open "SELECT id FROM circle", cn, adOpenForwardOnly, adLockReadOnly, adCmdText
pt1 = obj.Center
If Not FindObj(rst, obj.ObjectID) Then
cmd.CommandText = "INSERT INTO circle(id,CenX,CenY,Rad) VALUES(" & _
"'" & obj.ObjectID & "'," & pt1(0) & "," & pt1(1) & "," & obj.Radius & ");"
Else
cmd.CommandText = "UPDATE circle SET CenX=" & pt1(0) & ",CenY=" & pt1(1) & _
",Rad=" & obj.Radius & " WHERE id='" & obj.ObjectID & "';"
End If
cmd.Execute
rst.Close
'将原程序的arc改为
Case "AcDb3DSOLID":
rst.Open "SELECT id FROM 3DSOLID", cn, adOpenForwardOnly, adLockReadOnly, adCmdText
pt1 = obj.Center
If Not FindObj(rst, obj.ObjectID) Then
cmd.CommandText = "INSERT INTO 3DSOLID(id,CenX,CenY,Rad,StartAng,EndAng) VALUES(" & _
"'" & obj.ObjectID & "'," & pt1(0) & "," & pt1(1) & "," & obj.Radius & "," & _
obj.StartAngle & "," & obj.EndAngle & ");"
Else
cmd.CommandText = "UPDATE 3DSOLID SET CenX=" & pt1(0) & ",CenY=" & pt1(1) & _
",Rad=" & obj.Radius & ",StartAng=" & obj.StartAngle & ",EndAng=" & _
obj.EndAngle & " WHERE id='" & obj.ObjectID & "';"
End If
cmd.Execute
rst.Close
End Select
Next obj
Debug.Print obj.ObjectName
Debug.Print obj.ObjectID
打印结果
AcDb3dSolid ----- 3dsolid
2129993344
AcDbLine ---------- line
2129993352
-----------------------------
"3DSOLID"的特性表为
((-1 . ) (0 . "3DSOLID") (330 . ) (5 .
"88") (100 . "AcDbEntity") (67 . 0) (410 . "Model") (8 . "0") (100 .
"AcDbModelerGeometry") (70 . 1) (1 . "mogoo kk m o ")
求教
这段程序如何改，理由是什么？
同理，还有插入的块程序如何写，理由是什么？
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