如以下程式:
本人先定义chang为双精度,然后通过输入chang来定Hchang,可是发现输入整数后,Hchang也不为0,请问为什么?
Dim chang As Double, Hchang As Double
chang = InputBox("input a double", "input")
If VarType(chang) = vbInteger Then
Hchang = 0
Else
Hchang = Val(Right(CStr(chang), 1))
End If
MsgBox Hchang